7p^2+6=13p

Solution for 7p^2+6=13p equation:

7p^2+6=13p

We move all terms to the left:

7p^2+6-(13p)=0

a = 7; b = -13; c = +6;
Δ = b2-4ac
Δ = -132-4·7·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-1}{2*7}=\frac{12}{14}
=6/7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+1}{2*7}=\frac{14}{14}
=1
$